Question

How much heat is needed to raise the temperature of 2 kg of lead from room temperature to 350 degrees Celsius?

Answer 1

Question 31348

Heat needed to heat lead can be calculated according to formula $Q=cm\delta T$, where $c$ is the heat capacitance of lead ($c=130\frac{J}{kg\cdot C}$), m is the mass of the lead ($m=2kg$) and $\delta T=T_{2}-T_{1}$ is the difference between $T_{2}=350C$ and $T_{1}=20C$(room temperature). Perfoming the calculation, obtain $Q=85800J=85.8kJ$ of energy.