Answer to Question #313136 in Molecular Physics | Thermodynamics for Andy

Question

b) A 20kg mass of Aluminum of specific heat Capacity OF 900kg /k was heated from 2k to 12k. Determine the

amount of heat Energy required

Answer 1

$Q=cm\Delta{T}=900\frac{J}{kg\times{K}}\times20\ kg\times(12\ K-2\ K)=180000\ J=180\ kJ$

Answer: 180 kJ