How much energy is needed to melt a 100-g sample of aluminum whose initial temperature is 20 degrees celcius.
Solution.
m=0.1kg;m=0.1kg;m=0.1kg;
t0=20oC;t_0=20^oC;t0=20oC;
t=660oC;t=660^oC;t=660oC;
λ=390⋅103J/kg;\lambda=390\sdot10^3J/kg;λ=390⋅103J/kg;
c=920J/kgoC;c=920J/{kg^oC};c=920J/kgoC;
Q=cmΔt+λm;Q=cm\Delta t+\lambda m;Q=cmΔt+λm;
Q=920⋅0.1⋅(660−20)+390⋅103⋅0.1=97880J;Q=920\sdot0.1\sdot(660-20)+390\sdot10^3\sdot0.1=97880J;Q=920⋅0.1⋅(660−20)+390⋅103⋅0.1=97880J;
Answer: Q=97880J.Q=97880J.Q=97880J.
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