Show that 1.0 mol of ideal gas under STP (standard temperature of exactly 0 oC and pressure of exactly 1.0
atm or 101.3 kPa) occupies a volume of 22.4 L.
Solution.
"\\nu=1 mol;"
"T=273K;"
"P=101300Pa;"
"PV=\\nu RT\\implies V=\\dfrac{\\nu RT}{P};"
"V=\\dfrac{1\\sdot8.31\\sdot273}{101300}=0.0224m^3=22.4L;"
Answer: "V=22.4L;"
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