Question

Show that 1.0 mol of ideal gas under STP (standard temperature of exactly 0 oC and pressure of exactly 1.0

atm or 101.3 kPa) occupies a volume of 22.4 L.

Answer 1

Solution.

$\nu=1 mol;$

$T=273K;$

$P=101300Pa;$

$PV=\nu RT\implies V=\dfrac{\nu RT}{P};$

$V=\dfrac{1\sdot8.31\sdot273}{101300}=0.0224m^3=22.4L;$

Answer: $V=22.4L;$