Solution.
r=0.025m;
L=0.056m;
T=20OC;
ρ=8960kg/m3;
T1=85oC;
m=Vρ;
V=SL=πr2L;
V=3.14⋅0.0252⋅0.056=1.1⋅10−4m3;
m=1.1⋅10−4⋅8960=0.9856kg;
V1=V(1+βΔT);
V1=1.1⋅10−4(1+5.1⋅10−6⋅65)=1.1004⋅10−4m3;
ρ1=V1m;
ρ1=1.1004⋅10−40.9856=8956kg/m3;
Answer:ρ1=8956kg/m3.
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