Question #308516

an aluminum tube with a 15 inch diameter with an average speed of 150 ft/min and specific volume of


Expert's answer

m˙=ρV˙=ρSh˙=πρd24h˙=14 ts.\dot m=\rho\dot V=\rho S\dot h=\pi\rho\frac{d^2}4 \dot h=14~\frac ts.


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