Answer to Question #307736 in Molecular Physics | Thermodynamics for Junior Pyakara

Question

two water tanks are connected to each other through a mercury manometer with inclined tubes as, shown in figure. if the pressure difference between the two tanks is 20 kPa . calculate a and angle teta

Answer 1

Solution;

$P_A+\rho_wg(a)+\rho_mg(2a)=P_B+\rho_wg(a)$

Rewrite;

$P_A+\rho_mg(2a)=P_B$

From which;

$a=\frac{P_B-P_A}{2\rho_mg}$

By direct substitution of values;

$a=\frac{20×10^3}{2×13600×9.81}=0.0749m$

From geometry;

$26.8sin\theta=2a$

$sin\theta=\frac{2a}{26.8}=\frac{2×0.0749}{0.268}$

$sin\theta =0.5593$

$\theta=34.01°$