Question

how much heat is given out when 50g of steam at 100°C cool to water at 28°C?

Answer 1

Answer

$Heat is given out\\ Q = m\> C_{p}\times \Delta t\\Q=m×C p ​ ×Δt Q = 0.05 \times 2.3\times10^{-3}\times (1000-280) =82800 kJQ=0.05×2.3×10 −3 ×(1000−280)\\=82800kJ$