Solution;
m=2lb
(a)
P1=400psia
P2=199.7psia
V1=P1mRT1=400×1442×53.34×960=1.778ft3
V2=P2mRT2
V2=199.7×1442(53.34)(960)=3.561ft3
V3=p3mRT3
V3=24.97×1442(53.34)×530=7.849ft3
(b)
ΔS1−2=mRlnv1v2
ΔS1−2=2×77853.34ln1.7783.561=0.0952Btu/°R
(c)
Qa=T1Δs=960×0.0952=91.43Btu
Qr=−T3Δs=−530×0.0952=−50.46Btu
(d)
η=QW
W=Qa−Qr =40.97Btu
η=91.4340.97=0.4481
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