Dry hydrogen is trapped by a pellet of mercury in a uniform capillary tube closed at one end. If the length of the
column of hydrogen at 270oC is 1.0m, at what temperature will the length be 1.20m?
t2=l2(t1+273)l1−273=379°C.t_2=\frac{l_2(t_1+273)}{l_1}-273=379°C.t2=l1l2(t1+273)−273=379°C.
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