Calculate the temperature at which root mean square speed of gas molecules is double of its speed at 27°c pressure remaining constant
v=3RTM,v=\sqrt{\frac{3RT}M},v=M3RT,
v∼T,v\sim \sqrt T,v∼T,
T2=22T1=4T1=1200 K=927°C.T_2=2^2T_1=4T_1=1200~K=927°C.T2=22T1=4T1=1200 K=927°C.
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