Question #300217

Ten kilograms of steam at 100°C is condensed is 500 kg of water at 40.0°C. What is the resulting temperature?

1
Expert's answer
2022-02-20T15:45:01-0500

cm1(t−t1)=Lm2,cm_1(t-t_1)=Lm_2,

t=t1+Lm2cm1=51.0°C.t=t_1+\frac{Lm_2}{cm_1}=51.0°C.


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