How much heat is required to change 10 g of ice at exactly 0°C to steam at 100°C.
Total heat absorbed
ΔHfusion+ΔHtemp.rise+ΔHvap.ΔH_{ fusion} +ΔH _{temp.rise} +ΔH _{vap.}ΔHfusion+ΔHtemp.rise+ΔHvap.
=10×80+10×1×100+10×540=7200cal=10×80+10×1×100+10×540\\=7200cal=10×80+10×1×100+10×540=7200cal
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