Question #299238

 


a) 0.056m³ of air at 1.38 bar are compressed isothermally to a volume of 0.014m³. 

Determine the work energy required for the compression.


b) compare this to the work energy which would be required for an adibatic compression through the same volume ratio. For air R= 0.287KN and ➰ = 1.4


1
Expert's answer
2022-02-18T08:22:18-0500

Given:

V1=0.056m3V_1=0.056\:\rm m^3

V2=0.014m3V_2=0.014\:\rm m^3

p1=1.38105Pap_1=1.38*10^5\:\rm Pa


(a) T=constT=const

W=p1V1lnV2V1W=p_1V_1\ln\frac{V_2}{V_1}

W=1.381050.056ln0.0140.056=10713JW=1.38*10^5*0.056\ln\frac{0.014}{0.056}=-10713\:\rm J

(b) δQ=0\delta Q=0

W=p1V1((V2V1)1γ1)1γW=\frac{p_1V_1((\frac{V_2}{V_1})^{1-\gamma}-1)}{1-\gamma}

W=1.381050.056((0.0140.056)11.41)11.4W=\frac{1.38*10^5*0.056((\frac{0.014}{0.056})^{1-1.4}-1)}{1-1.4}

W=14318JW=-14318\:\rm J


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