Answer to Question #296664 in Molecular Physics | Thermodynamics for dandan

Question #296664

 A feather is dropped on the moon from a height of 1.40 meters. The acceleration of gravity on the moon is 1.67 m/s^2. Determine the time for the feather to fall to the surface of the moon. *


1
Expert's answer
2022-02-13T12:14:03-0500

Given:

h=1.40mh=1.40\rm\: m

g=1.67m/s2g=1.67\:\rm m/s^2


The time required to get a surface of Moon by the feather

t=2hg=21.401.67=1.29st=\sqrt{\frac{2h}{g}}=\sqrt{\frac{2*1.40}{1.67}}=1.29\:\rm s


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