Answer to Question #296664 in Molecular Physics | Thermodynamics for dandan

Question

 A feather is dropped on the moon from a height of 1.40 meters. The acceleration of gravity on the moon is 1.67 m/s^2. Determine the time for the feather to fall to the surface of the moon. *

Answer 1

Given:

$h=1.40\rm\: m$

$g=1.67\:\rm m/s^2$

The time required to get a surface of Moon by the feather

$$t=\sqrt{\frac{2h}{g}}=\sqrt{\frac{2*1.40}{1.67}}=1.29\:\rm s$$