Question

150 j of heat energy is required to increase the temperature of a body by 6.0°c , calculate the heat capacity of the body and thus it's specific heat capacity if it's mass is 0.1kg

Answer 1

Answer

Heat required Q=150J

Increment in temperature

$\Delta T= 6°C$

Mass m=0.1Kg

So heat capacity is given by

$C=\frac{ Q}{\Delta T}\\=\frac{ 150}{6}\\=75J/°C$

Specific heat capacity

$C_m=\frac{ Q}{m\Delta T}\\=\frac{ 150}{0.1\times6}\\=150J/°C-Kg$