Answer to Question #291373 in Molecular Physics | Thermodynamics for Chieng Ruey

Question

A helium gas is at pressure of 1atm and temperature of 0°C. If its pressure is dropped to its initial pressure, when its volume is kept constant. (a) calculate the work done by the gas. (b) what is the final temperature of the gas. (b) what is the work done by the if its volume becomes twice as initial volume and it return to its initial temperature.

Answer 1

$p=101325~Pa,$

$T=273~K,$

$A=\nu RT=2.3~kJ,$

$T_1=2T=246~K,$

$A_1=\nu RT\log\frac{V_2}{V_1}=1.6~kJ.$