An ideal gas expands isothermally, performing 3.40x103 J of work in the process.
Calculate (a) the change in the internal energy of the gas, and (b) the heat
absorbed during the expansion.
(a) Since the temperature is constant and the change in internal energy depends on the change in temperature, "\\Delta U=0."
(b) According to the first law of thermodynamics, "Q=\\Delta U+W=0+3.4\u00b710^3=3.4\u00b710^3\\text{ J}."
Comments
Leave a comment