Answer to Question #288454 in Molecular Physics | Thermodynamics for tepay

Question

A tall unclothed athlete with a skin temperature of 34^oC stands in a dark room with a temperature o 23^oC. The athlete’s skin has a surface area of 1.7m². What is the rate of heat transfer via radiation from the athlete? (e_skin  = 0.97)

Answer 1

$Q(t)=ε σAT^4$

$ε_{skin}=0.97$

$σ=5.67×10^{-5}$

$A=1.7m^2$

$T=307K$

$Q(t)=0.97×5.67×10^{-8}×1.7×307^4$

$Q(t)=488.55Watt$