Answer to Question #288303 in Molecular Physics | Thermodynamics for harry

Question #288303

Determine change of entropy for a reaction: H2(g) + I2(g) → 2HI(g)

H2(g) - 130.58 I2(J/mol.K)

I2 - 116.73(J/mol.K)

HI(g) - 206.3(J/mol.K) 


1
Expert's answer
2022-01-24T18:44:25-0500

H2+I22HIH_2+I_2\rightarrow2HI


S°rxn=2S(HI)[S(H2)+S(I2)]∆S°_{rxn}=2S(HI)-[S(H_2)+S(I_2)]

Put value


S°rxn=2×206.3[(130.58+116.73)]∆S°_{rxn}=2\times206.3-[(130.58+116.73)]

S°rxn=(412.6247.31)J/K∆S°_{rxn}=(412.6-247.31)J/K

S°rxn=165.29J/K∆S°_{rxn}=165.29J/K


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