Calculate the entropy change for 3 kg of ice melting. Given Hf = 333.5 kJ/kgH20
S=mHT=3⋅333500273=3.7 kJK.S=\frac{mH}T=\frac{3\cdot 333500}{273}=3.7~\frac{kJ}K.S=TmH=2733⋅333500=3.7 KkJ.
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