Question #288297

3.5 moles of CO2 in a container were expanded against an external pressure of 2.5 atm to a final volume of 37L. The initially pressure and temperature were 8 atm and 30⁰C, respectively. Calculate the final temperature and the work done for the process.


1
Expert's answer
2022-01-25T07:11:22-0500

Gives

P2=2.5atmn=3.5molV2=37LP_2=2.5atm \\n=3.5mol\\V_2=37L

Ideal gas equation

PV=nRT

T2=P2V2nRT_2=\frac{P_2V_2}{nR}

T2=2.5×373.5×0.0821=321.90KT_2=\frac{2.5\times37}{3.5\times0.0821}=321.90K

T2=321.90273=48.9°CT_2=321.90-273=48.9\degree C

Work

W=nCvΔTW=nC_vΔT

W=3.5×25.08(321.90300)W=3.5\times25.08(321.90-300)

W=1922.382JW=1922.382J

W=1.922KJ


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