Answer to Question #288295 in Molecular Physics | Thermodynamics for harry

Question

Determine the temperature (in Kelvin) for 1 mol of gas at 10 atm with a volume of 15L

Answer 1

Answer

No. Of moles n= 1

Volume

V=15L=$15\times10^{-3}m^3$

Presure

P=1atm=$1.01\times10^{5}Pa$

Using ideal gas equation

$PV=nRT$

So temperature

$T=\frac{PV}{nR}$

Putting all values

$T=\frac{1.01\times10^5\times15\times10^{-3}}{1\times8.314}\\=182K$