Question

210 J of heat is added to a system having an internal energy of 58 J. Calculate the amount of the external work done by the system.

Answer 1

From the first law of thermodynamics

$\Delta U=Q+W$

$\Delta U=58J$

$Q=210J$

$W=?$

$\therefore W=58-210 = -152J$

The amount of external work done is 152J