Answer to Question #288289 in Molecular Physics | Thermodynamics for harry

Question

A silver teaspoon at temperature 7⁰C is placed in a cup of hot coffee at temperature 93⁰C. If the teaspoon has a mass of 32 g and the hot coffee has 90g of mass, determine the final temperature of the silver teaspoon? Ccoffee = 1 cal/g.K Csilver = 0.0558 cal/g.K

Answer 1

Heat loss by Coffee = - Heat gain by silver teaspoon.

From $Q= mc\theta$

$90×1×(366-T_2)=-32×0.0558×(280-T_2)$

$=32940-90T_2=-499.97+1.79T_2$

$T_2=364.31K =91.31°C$