Question #287481

An ideal gas expands isothermally ( T = 410 K) from a volume of 2.50 l and a

pressure of 7.5 atm to a pressure of 1.0 atm. What is the entropy change for this

process? [Ans = 9.3 J/K]


1
Expert's answer
2022-01-18T13:42:55-0500

Find the final volume:


V2=V1P1P2=18.75 L.V_2=V_1\dfrac{P_1}{P_2}=18.75\text{ L}.


The entropy change for this process:


ΔS=RlnV2V1=16.8 J/K.\Delta S=R\ln\dfrac{V_2}{V_1}=16.8\text{ J/K}.



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