A 50-g ice cube at -4
oC is dropped into an insulated container conatining 200mL at 25°CWhen thermal equilibrium is reached, the temperature of water dropped to 9°C. How much heat
is gained by the ice cube ?
Solution.
mc=0.05kg;m_c=0.05kg;mc=0.05kg;
t1=−4oC;t_1=-4^oC;t1=−4oC;
t=9oC;t=9^oC;t=9oC;
Vw=0.2⋅10−3m3;V_w=0.2\sdot10^{-3}m^3;Vw=0.2⋅10−3m3;
t2=25oC;t_2=25^oC;t2=25oC;
Qw−=cwmwΔt;Q_w^-=c_wm_w\Delta t;Qw−=cwmwΔt;
mw=ρwVw;m_w=\rho_wV_w;mw=ρwVw;
mw=103⋅0.2⋅10−3=0.2kg;m_w=10^3\sdot0.2\sdot10^{-3}=0.2kg;mw=103⋅0.2⋅10−3=0.2kg;
Qw−=4200⋅0.2⋅(25−9)=13440J;Q_w^-=4200\sdot0.2\sdot(25-9)=13440J;Qw−=4200⋅0.2⋅(25−9)=13440J;
Qc+=Qw−=13440J;Q_c^+=Q_w^-=13440J;Qc+=Qw−=13440J;
Answer: 13440J.13440J.13440J.
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