There is a 50 meter long train. It magically goes at 60% the speed of light (0.6c). How long will it appear to be to an outside observer?
Answer
Train length
L=50m
Moving v=0.6c
c is speed of light
So train will appear to be to an outside observer as
"L'=L\\sqrt{1-\\frac{v^2}{c^2}}"
"L'=50\\sqrt{1-\\frac{(0.6c)^2}{c^2}}"
"L'=50\\sqrt{0.64}=40m"
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