The resistance of the conductor is 20ohms at 20°C and 50ohms at 500°C. Calculate the resist of these conductor at 80°C
Solution;
Given ;
RT=20ΩR_T=20\OmegaRT=20Ω at T=20°cT=20°cT=20°c
RT′=50ΩR_{T'}=50\OmegaRT′=50Ω at T′=500°cT'=500°cT′=500°c
Resistance at a given temperature;
RT′=RT[1+α(T′−T)]R_{T'}=R_{T}[1+\alpha(T'-T)]RT′=RT[1+α(T′−T)]
Substitute;
50=20[1+α(500−20)]50=20[1+\alpha(500-20)]50=20[1+α(500−20)]
Therefore;
α=1320\alpha=\frac{1}{320}α=3201
Now we obtained for R at 80°c;
RT′′=20[1+1320(80−20)]R_{T''}=20[1+\frac{1}{320}(80-20)]RT′′=20[1+3201(80−20)]
RT′′=23.75ΩR_{T''}=23.75\OmegaRT′′=23.75Ω
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