Question #285767

A spherical shaped vessel of 2 m diameter is 90 mm thick. Find the rate of heat leakage, if the temperature difference between the inner and outer surfaces is 220°C Thermal conductivity of the material of the sphere is 0.09 W/m°C.





1
Expert's answer
2022-01-10T09:09:43-0500

Solution.

r2=2m;r_2=2m;

r1=1.91m;r_1=1.91m;

Δt=220oC;\Delta t=220^oC;

k=0.09W/moC;k=0.09W/m^oC;

Q=ΔtR;Q=\dfrac{\Delta t}{R};

R=r2r14πkr1r2;R=\dfrac{r_2-r_1}{4\pi k r_1r_2};

R=21.9143.140.0921.91=0.094.32=0.021oC/W;R=\dfrac{2-1.91}{4\sdot3.14\sdot0.09\sdot2\sdot1.91}=\dfrac{0.09}{4.32}=0.021^oC/W;

Q=2200.021=10476W=10.476kW;Q=\dfrac{220}{0.021}=10476W=10.476kW;

Answer: Q=10.476kW.Q=10.476kW.



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