Question

Find the minimum kinetic energy (in MeV) in the lab system needed by an alpha particle to cause

the reaction:

7𝑁

14 + 𝛼 → 8𝑂

17 + 1𝐻

1

Given that: m(

14N) = 14.00307 u; m(α) 4.003879 u; m(

1H) = 1.00783 u; m(

17O) = 17.0013 u;

1 𝑢 = 931.5 𝑀𝑒𝑉/𝑐

2

Answer 1

$E=\Delta mc^2=(14.00307+4.003879-1.00783-17.0013)\cdot 931 .5=2.03~MeV.$