Question #284062

A cylinder of mass m and radius R has a moment of inertia of . The cylinder is released from rest at a height  on an inclined plane, and rolls down the plane without slipping. What is the velocity of the cylinder when it reaches the bottom of the incline?


1
Expert's answer
2022-01-04T11:14:58-0500

mgh=0.5mv2mgh=0.5mv^2 +0.5Iω2+0.5I \omega^2

mgh=0.5mv2+0.25mv2mgh=0.5mv^2+0.25mv^2

v=4/3ghv=\sqrt{4/3gh}


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