What is the angular acceleration of a ball that starts at rest and increases its angular velocity uniformly to 5 rad/s in 10 s?
Solution:
ω=ωo+ϵt → ϵ = ωt\frac{\omega}{t}tω=510\frac{5}{10}105= 0.5 (rads2\frac{rad}{s^2}s2rad)
Answer:
Angular acceleration of a ball is 0.5 rads2\frac{rad}{s^2}s2rad
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