A 0.5 kg of air is compressed reversibly and adiabatically from 80 kPa and 60°C to 0.4 MPa and is then expanded at constant pressure to the original volume. Sketch the process on p-V and T-S diagrams, compute work transfer, heat transfer and change in entropy for whole path
V0=mRT0p0=0.514 m3,V_0=\frac{mRT_0}{p_0}=0.514~m^3,V0=p0mRT0=0.514 m3,
γ=cpcV=1.4,\gamma=\frac{c_p}{c_V}=1.4,γ=cVcp=1.4,
Wc=−52mRT0((p1p0)1−1γ−1)=−60 kJ,W_c=-\frac 52mRT_0((\frac{p_1}{p_0})^{1-\frac 1{\gamma}}-1)=-60~kJ,Wc=−25mRT0((p0p1)1−γ1−1)=−60 kJ,
V1=V0(p1p0)γ=0.163 m3,V_1=V_0(\frac{p_1}{p_0})^{\gamma}=0.163~m^3,V1=V0(p0p1)γ=0.163 m3,
T1=p1V1mR=527.3 K,T_1=\frac{p_1V_1}{mR}=527.3~K,T1=mRp1V1=527.3 K,
T2=p2V2mR=1664.8 K,T_2=\frac{p_2V_2}{mR}=1664.8~K,T2=mRp2V2=1664.8 K,
Qc=0,Q_c=0,Qc=0,
Qe=mcpΔT=571.7 kJ,Q_e=mc_p\Delta T=571.7~kJ,Qe=mcpΔT=571.7 kJ,
We=pΔV=140.5 kJ,W_e=p\Delta V=140.5~kJ,We=pΔV=140.5 kJ,
Q=Qc+Qe=571.7 kJ,Q=Q_c+Q_e=571.7~kJ,Q=Qc+Qe=571.7 kJ,
W=Wc+We=80.5 kJ.W=W_c+W_e=80.5~kJ.W=Wc+We=80.5 kJ.
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