Question #283609

7/9(3x)cube

1
Expert's answer
2021-12-30T11:53:45-0500

7/9(3x)cube is


79⋅(3x)3=79⋅27x3=79⋅(9⋅3)x3=7⋅3x3=21x3.\dfrac79·(3x)^3=\dfrac79·27x^3=\dfrac79·(9·3)x^3=7·3x^3=21x^3.


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