7/9(3x)cube is dfrac79 u00b7(3x)^3= dfrac79 u00b727x^3= dfrac79 u00b7(9 u00b73)x^3=7 u00b73x^3=21x^3.

Answer in Molecular Physics | Thermodynamics for Svk #283609

Question #283609

7/9(3x)cube

7/9(3x)cube is

\dfrac79·(3x)^3=\dfrac79·27x^3=\dfrac79·(9·3)x^3=7·3x^3=21x^3.

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