Answer to Question #283017 in Molecular Physics | Thermodynamics for Jack lakos

Question

10 kg of air is contained in a constant volume container at a temperature of AA°C and a pressure of 150kPa. How much air is pressed into the container, its pressure is 250kPa and its temperature is BB°C? (AA and BB are a two-digit number ending in 0 or 5)

Answer 1

$p_1V=\frac mMRT_1,$

$p_2V=\frac{ m+dm}MRT_2,\implies$

$\frac{p_2}{p_1}=(1+\frac{dm}m)\frac{T_2}{T_1},$

$dm=m(\frac{p_2T_1}{p_1T_2}-1).$