Answer to Question #281764 in Molecular Physics | Thermodynamics for Kurapikachu

Question

4. A fluid moves in a steady flow manner between two sections in the same

flowline. At section 1: A = 0.10 m2, V, = 6 m/s, v1 = 0.33 m /kg. At

section 2: A2 = 0.2 m2, P2 = 0.27 kg/mº. Calculate for the velocity of flow

of section 2.

A. 37.63 m/s

C. 40.62 m/s

B. 33.67 m/s*

D. 46.02 m/s

Answer 1

$\frac{A_1v_1}{V_1}=\rho_2A_2v_2,\implies$

$v_2=\frac{A_1v_1}{V_1\rho_2A_2}=33.67~\frac ms.$