Question #278797

Find the values of Cp and ᵞ for a gas whose gas




constant is 0.324 kJ/kg K and Cv = 0 84 kJ/kg K.




If 2.25 kg of this gas with an initial volume of




1.15 m3 undergoes a process during which its




pressure remains constant at 7 bar and its




temperature becomes 280‘C at the end of the




process, calculate: (a) the change in internal




energy, (b) the change in enthalpy, (c) the




transferred heat, and (d) the work done.

1
Expert's answer
2021-12-13T11:05:56-0500

Internal energy


U=mCvTU=2.25×0.84×553=1045.17KJU=mC_v∆T \\U=2.25\times0.84\times553=1045.17KJ

Enthalpy

1bar=105pa1bar=10^5 pa


H=U+PVH=1045.17+7×105×1.15H=1045.17+805H=1850.17KJH=U+PV \\H=1045.17+7\times10^5\times1.15 \\H=1045.17+805\\H=1850.17KJ

Work done (W)=PdV

W=7×105×1.15=805KJ7\times10^5\times1.15=805KJ


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