Question #278420

Nitrogen is stored in a 0.425 m² tank at 560 atm, 456 K. Determine the mass of nitrogen in the tank using (a) ideal gas theory, (b) the compressibility factor, (c) van der Waals equation.

Expert's answer

Ideal gas equation

PV=nRTPV=nRT

V=nRTPV=\frac{nRT}{P}


V=1×8.31×456560×105=3707.28560×105=6.760×105m3V=\frac{1\times8.31\times456}{560\times10^5}=\frac{3707.28}{560\times10^5}=6.760\times10^{-5} m^3

560×105×6.76×105=8.31×456560\times10^5\times6.76\times10^{-5}=8.31\times456

LHS=RHS


Compressibility factor

Z=PVRTZ=\frac{PV}{RT}

Z=560×105×6.760×1058.31×456=0.999Z=\frac{560\times10^5\times6.760\times10^{-5}}{8.31\times456}=0.999

Wander val equation

(P+an2V2)(Vnb)=nRT(P+\frac{an^2}{V^2})(V-nb)=nRT

n=1mol

(P+aV2)(Vb)=RT(P+\frac{a}{V^2})(V-b)=RT


(560×105+a6.76×105)(6.76×105b)=8.31×456(560\times10^5+\frac{a}{6.76\times10^{-5}})(6.76\times10^{-5}-b)=8.31\times456

LHS=RHS


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