What is the angular velocity of an object traveling in a circle of radius 0.75 with a linear speed of 3.5m/s?
The angular velocity ω\omegaω is ω=VR=3.5 m/s0.75 m≈4.67 rad/s.\omega = \dfrac{V}{R} = \dfrac{3.5\,\mathrm{m/s}}{0.75\,\mathrm{m}} \approx 4.67\,\mathrm{rad/s}.ω=RV=0.75m3.5m/s≈4.67rad/s.
Why is this formula correct? The angular velocity ω\omegaω is ω=2πT=2π2πR/V=VR.\omega = \dfrac{2\pi}{T} = \dfrac{2\pi}{2\pi R/V} = \dfrac{V}{R}.ω=T2π=2πR/V2π=RV.
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