Question

Calculate the thrust of a steel ball of 10cm radius immersed in water. (Archimedes Principle) Show solution.

Answer 1

The volume of the ball:

$$V=\frac 43\pi r^3=4.19·10^{-3}\text{ m}^3.$$

The buoyancy force:

$$F=\rho gV=41.1\text{ N}.$$