Answer to Question #275450 in Molecular Physics | Thermodynamics for nats

Question

the water flows in the channel 844 mm x 586 mm at the rate of 8 m/sec. What is the volume flow in ft^3/sec?

Answer 1

Given:

$A=\rm 844\: mm\times 586\: mm=0.495\: m^2$

$v=\rm 8 \: m/s$

The volume flow

$$\frac{dV}{dt}=Av\\ =\rm 0.495\: m^2*8\: m/s=3.96\: m^3/s=140\: ft^3/s$$