While the temperature remains constant at 38oC, 2.5 kg of a certain ideal gas whose Cp = 1.1724 kJ/kg-K, Cv = 0.8375 kJ/kg-K rejects 300kJ of heat. If p1 = 586kPa, find: (a) p2, (b) V1 and V2.
ν=m(cp−cV)R=100.8 mol,\nu=\frac{m(c_p-c_V)}R=100.8~mol,ν=Rm(cp−cV)=100.8 mol,
a)
Q=νRTlnp1p2, ⟹ Q=\nu RT\ln\frac{p_1}{p_2},\impliesQ=νRTlnp2p1,⟹
p2=p1e−QνRT=185 kPa,p_2=p_1e^{-\frac Q{\nu RT}}=185~kPa,p2=p1e−νRTQ=185 kPa,
b)
V1=νRTp1=0.44 m3,V_1=\frac{\nu RT}{p_1}=0.44~m^3,V1=p1νRT=0.44 m3,
V2=νRTp2=1.41 m3.V_2=\frac{\nu RT}{p_2}=1.41~m^3.V2=p2νRT=1.41 m3.
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