0.085 m3 of air are compressed isentropically from 1937 kPa and -4 oC to 5873 kPa . Find (a) t2 in oC and V2, (b) Wnf, and © H and U.
T2=T1(P2P1)k−1kT_2=T_1( \frac{P_2}{P_1} )^ \frac{k-1}{k}T2=T1(P1P2)kk−1
Where:
T2=T_2=T2= final temperature
T1=269KT_1=269KT1=269K
P2=5873kPaP_2=5873kPaP2=5873kPa
P1=1937kPaP_1=1937kPaP1=1937kPa
k=1.4=k=1.4=k=1.4= constant
T2=269×(58731937)1.4−11.4=369.3K=96.30CT_2=269×( \frac{5873}{1937} )^ \frac{1.4-1}{1.4} =369.3K=96.3^0CT2=269×(19375873)1.41.4−1=369.3K=96.30C
Also:
T2T1=(V1V2)k−1\frac{T_2}{T_1} =(\frac{V_1}{V_2} )^ {k-1}T1T2=(V2V1)k−1
369.3269=(0.085V2)(1.4−1)\frac{369.3}{269}=(\frac{0.085}{V_2})^{(1.4-1)}269369.3=(V20.085)(1.4−1)
V2=0.0385M3V_2=0.0385M^3V2=0.0385M3
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments