Question #274648

0.085 m3 of air are compressed isentropically from 1937 kPa and -4 oC to 5873 kPa . Find (a) t2 in oC and V2, (b) Wnf, and © H and U.


1
Expert's answer
2021-12-03T10:59:59-0500

T2=T1(P2P1)k1kT_2=T_1( \frac{P_2}{P_1} )^ \frac{k-1}{k}

Where:

T2=T_2= final temperature

T1=269KT_1=269K

P2=5873kPaP_2=5873kPa

P1=1937kPaP_1=1937kPa

k=1.4=k=1.4= constant

T2=269×(58731937)1.411.4=369.3K=96.30CT_2=269×( \frac{5873}{1937} )^ \frac{1.4-1}{1.4} =369.3K=96.3^0C

Also:

T2T1=(V1V2)k1\frac{T_2}{T_1} =(\frac{V_1}{V_2} )^ {k-1}

369.3269=(0.085V2)(1.41)\frac{369.3}{269}=(\frac{0.085}{V_2})^{(1.4-1)}

V2=0.0385M3V_2=0.0385M^3




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