Question #274141

A polytropic process of air from 1034 kPa, 149 deg. C and 0.028 m3 occurs to 138 kPa in accordance with pV1.3 = C. Determine


(a) the final temperature in deg. C


(b) the change in internal energy in kJ


(c) the work nonflow in kJ


(d) the heat in kJ from the formula using polytropic specific heat

Expert's answer

a)

T2=T1(p2p1)1−1γ=265 K=−8°C,T_2=T_1(\frac{p_2}{p_1})^{1-\frac 1{\gamma}}=265~K=-8°C,

b)

A=p1V1γ−1(1−(p2p1)1−1γ)=35.8 kPa.A=\frac{p_1V_1}{\gamma-1}(1-(\frac{p_2}{p_1})^{1-\frac 1{\gamma}})=35.8~kPa.


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