Question #273792

While the temperature remains constant at 38 deg. C, 2.5 kg of a certain ideal gas whose Cp = 1.1724 kJ/kg-K, Cv = 0.8375 kJ/kg-K rejects 300kJ of heat. If p1 = 586kPa, determine:

(a) the final pressure in kPa

(b) the initial volume in cubic meter

(c) the final volume in cubic meter


1
Expert's answer
2021-11-30T17:43:46-0500

Solution;

Given;

T1=T2=38°c=311KT_1=T_2=38°c=311K

m=2.5

Q=300kJQ=300kJ

P1=586kPaP_1=586kPa

Cp=1.1724kJ/kgKC_p=1.1724kJ/kgK

Cv=0.8375kJ/kgKC_v=0.8375kJ/kgK

R=CpCv=0.3349kJ/kgKR=C_p-C_v=0.3349kJ/kgK

From;

PV=mRTPV=mRT

We have;

V1=2.5×0.3349×311586=0.4443m3V_1=\frac{2.5×0.3349×311}{586}=0.4443m^3

Q=p1v1ln(v2v1)Q=p_1v_1ln(\frac{v_2}{v_1})

300=586×0.4443×ln(v20.4443)300=586×0.4443×ln(\frac{v_2}{0.4443})

V2=0.1404m3V_2=0.1404m^3

(a)

Final pressure in kPa

P2=V1V2P1=0.44430.1404×586=1854.4kPaP_2=\frac{V_1}{V_2}P_1=\frac{0.4443}{0.1404}×586=1854.4kPa

(b)

Initial volume in m3;

V1=0.4443m3V_1=0.4443m^3

(c)

Final volume;

V2=0.1404m3V_2=0.1404m^3





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