Solution;
Given;
T1=T2=38°c=311K
m=2.5
Q=300kJ
P1=586kPa
Cp=1.1724kJ/kgK
Cv=0.8375kJ/kgK
R=Cp−Cv=0.3349kJ/kgK
From;
PV=mRT
We have;
V1=5862.5×0.3349×311=0.4443m3
Q=p1v1ln(v1v2)
300=586×0.4443×ln(0.4443v2)
V2=0.1404m3
(a)
Final pressure in kPa
P2=V2V1P1=0.14040.4443×586=1854.4kPa
(b)
Initial volume in m3;
V1=0.4443m3
(c)
Final volume;
V2=0.1404m3
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