Answer to Question #271828 in Molecular Physics | Thermodynamics for MaTMaT

Question #271828

Air is compressed in a diesel engine from an initial pressure of 13 psia and a temperature of 120 F to one-twelfth of its original volume. Calculate the final temperature assuming the compression is adiabatic


1
Expert's answer
2021-11-26T10:28:36-0500

P1=13  psiaT1=120  °F=322.039  KV2=V112P_1 = 13 \; psia \\ T_1 = 120 \; °F = 322.039 \; K \\ V_2 = \frac{V_1}{12}

Adiabatic compression

P2P1=(V1V2)γT2T1=(V1V2)γ1P2=P1×(12)1.4=13×(12)1.4P2=421.499  psiaT2=T1×(V1V2)γ1=322.039×(12)0.4=870.123  KT2=1106.551  °F1010  °F\frac{P_2}{P_1} = (\frac{V_1}{V_2})^γ \\ \frac{T_2}{T_1} = (\frac{V_1}{V_2})^{γ-1} \\ P_2 = P_1 \times (12)^{1.4} \\ = 13 \times (12)^{1.4} \\ P_2 = 421.499 \; psia \\ T_2 = T_1 \times (\frac{V_1}{V_2})^{γ-1} \\ = 322.039 \times (12)^{0.4} \\ = 870.123 \; K \\ T_2 = 1106.551 \; °F ≈ 1010 \; °F


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!

Leave a comment