Question #26801

an ideal gas occupies a volume of 1.0 cubic cm at 20 degrees and atmosphere . determine the number of molecules of gas in the container .(b) if the pressure of the 1.0-cm cubic volume is reduced to 1.0*10 to the power negative 11 Pa(an extremely good vacuum )while the temperature remains constant , how many moles of gas remain in the container ?

Expert's answer

QUESTION:

an ideal gas occupies a volume of 1.0 cubic cm at 20 degrees and atmosphere.

(a) determine the number of molecules of gas in the container

(b) if the pressure of the 1.0-cm cubic volume is reduced to 1.0×1011Pa1.0 \times 10^{-11} \, \text{Pa} (while the temperature remains constant, how many moles of gas remain in the container?

SOLUTION:

a) According to the ideal gas law


p1V1=n1RTn1=N1NAp1V1=N1NARTN=p1V1NART=1.011051066.0210238.31(20+273)=2.51019\begin{array}{l} p_1 V_1 = n_1 R T \\ n_1 = \frac{N_1}{N_A} \\ p_1 V_1 = \frac{N_1}{N_A} R T \\ N = \frac{p_1 V_1 N_A}{R T} = \frac{1.01 \cdot 10^5 \cdot 10^{-6} \cdot 6.02 \cdot 10^{23}}{8.31 \cdot (20 + 273)} = 2.5 \cdot 10^{19} \\ \end{array}


b) Analogically:


p2V1=n2RTn2=p2V1RT=10111068.31(20+273)=4.11021mol\begin{array}{l} p_2 V_1 = n_2 R T \\ n_2 = \frac{p_2 V_1}{R T} = \frac{10^{-11} \cdot 10^{-6}}{8.31 \cdot (20 + 273)} = 4.1 \cdot 10^{-21} \, \text{mol} \\ \end{array}

ANSWER

a) 2.5×10192.5 \times 10^{19}

b) 4.1×1021mol4.1 \times 10^{-21} \, \text{mol}

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