Answer to Question #261754 in Molecular Physics | Thermodynamics for Syed fazal Abbas j

Question

Write down energy flow equation for non flow process. Estimate heat flow to/from the system.

Specific internal energy is 420kJ/kg at the beginning of the expansion and specific internal energy is

200kJ/kg at the end of the process. The work done by the system is 100kJ/kg during the process.

Answer 1

$U_1=420KJ/kg\\U_2=200KJ/kg$

$$∆U=U_2-U_1=420-200=220KJ/kg$$

$\frac{∆U}{m}=s∆T$

$s∆T=220KJ/kg$