Question #259313

A block of mass 2 kg is attached to a string that will break if the tension exceeds 500 N. If the block is whirled in a horizontal circle of radius 0.5 m, its maximum speed will be


1
Expert's answer
2021-11-01T17:15:22-0400

We know that

T=mv2rvmax=TrmT=\frac{mv^2}{r}\\v_{max}=\sqrt\frac{Tr}{m}


vmax=500×0.52=125=55=11.18m/secv_{max}=\sqrt\frac{500\times0.5}{2}=\sqrt{125}=5\sqrt5=11.18m/sec


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